Question

it sin theta=a/b cos theta=?​

Answer 1

Answer:

I DON,T UNDERSTAND

Step-by-step explanation:

Answer 2

Answer:

Sin^2 @ +cos^2@ = 1

a^2/b^2 + cos^2@ = 1

cos^2 @ = 1-a^2 /b^2

cos^2@ = b^2-a^2 / b^2

cos @ = under root b^2-a^2 / b^2