Question

It sin4- costo - Kt, tind
sin2o- cos 20 in term of k.

Answer 1

Answer:

${ \sin(x) }^{4} - { \cos(x) }^{4} = {k}^{4}$

If we use,

${a}^{2} - {b}^{2} = (a + b)(a - b)$

Then we get,

$( { \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2} )( { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} ) = {k}^{4}$

Now,

${ \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} = 1$

So we get,

${ \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2} = {k}^{4}$

So this is the answer.

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