Question

It T1 andT2 are the times of flight for two complementary angles then the range of projectiteR is given by

Answer 1

R=4gT1T2  

R=2gT1T2

R=14gT1T2

R=12gT1T2  

Solution :

T1=2usinθg,T2=2ucosθg

R=2(usinθ)(ucosθ)g

=2(gT12)(gT22)g

=12gT1T2