Question

It takes 1
1/ 13
m of cloth to make a pair of trousers. If the cloth needed to make 10 pairs of
trousers is cut out of a 20-m length of cloth, what length of cloth will be left?​

Answer 1

Answer:

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Answer 2

Answer:

Answer:

\begin{gathered}:\implies\text{One Pair of Trouser} \:\sf = 1{}^{3}\!/{}_{4}\\\\:\implies\text{One Pair of Trouser} \:\sf = \dfrac{7}{4}\\\\:\implies\text{Ten Pair of Trouser} \:\sf = \dfrac{7}{4} \times 10\\\\:\implies\text{Ten Pair of Trouser} \:\sf = \dfrac{7}{2} \times 5\\\\:\implies\text{Ten Pair of Trouser}\:\sf = \dfrac{35}{2} \end{gathered}

:⟹One Pair of Trouser=1

3

/

4

:⟹One Pair of Trouser=

4

7

:⟹Ten Pair of Trouser=

4

7

×10

:⟹Ten Pair of Trouser=

2

7

×5

:⟹Ten Pair of Trouser=

2

35

\rule{150}{1}

\boxed{\bf{\mid{\overline{\underline{\bigstar\:According\:to\:the\:Question :}}}}\mid}

∣

★AccordingtotheQuestion:

∣

\begin{gathered}\dashrightarrow\sf\:\:Cloth\:Left=Total-Cloth\:Used\\\\\\\dashrightarrow\sf\:\:Cloth\:Left=20-\dfrac{35}{2}\\\\\\\dashrightarrow\sf\:\:Cloth\:Left=\dfrac{(40-35)}{2}\\\\\\\dashrightarrow\sf\:\:Cloth\:Left=\dfrac{5}{2}\\\\\\\dashrightarrow\:\:\underline{\boxed{\sf Cloth\:Left=2{}^{1}\!/{}_{2} \:m}}\end{gathered}

⇢ClothLeft=Total−ClothUsed

⇢ClothLeft=20−

2

35

⇢ClothLeft=

2

(40−35)

⇢ClothLeft=

2

5

⇢

ClothLeft=2

1

/

2

m

⠀

\therefore\:\underline{\textsf{Length of cloth left will be \textbf{2${}^{\text1}\!/{}_{\text2}$ m}}}.∴

Length of cloth left will be 2

1

/

2

m

.

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