Question

It takes 10 s for the reactant to reduced 40 g reactant to 10g in a first order reaction. The rate constant of the reaction is
1) 0.1386 s
2)1.386 s
3)0.693 s
4)6.93 s​

Answer 1

Answer:

-1

Explanation:

As we know,

for a first order reaction,

t  

1/2

​

=  

k

0.693

​

=  

0.0693

0.693

​

=10min

Reactant after 10 min = 5 mol

Rate (  

dt

dx

​

)=k[A]=0.0693×5molmin  

−1