Math, asked by Hitron, 1 year ago

It takes 12 hrs for a bus to travel from X to Y. A bus leaves X for Y at 6pm, other bus leaves from Y to X at 8pm. At what time would the two trucks meet?(Explain) ( Assume the speeds of two busses equal)

Answers

Answered by Anonymous
0

Consider, from the 8pm when one bus have already completed the journey of two hours. Now, It will take 10 hours to reach Y and other bus should also take 10 hours to reach this point as their speed are equal.

  Now,  Consider distance=d

    Speed of either bus=d/10  (where, 10=time in hours)

Relative speed=d/10 + d/10 = d/5  (As they are heading in opposite direction)

 So, it means collectively they complete d/5 distance in one hour.

So, for crossing the distance d, they will take time = 5 hours from the initial time which was 8 pm. So, they meet each other at 1 AM.



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Answered by dineshanejamca
0

Answer:

Consider, from the 8pm when one bus have already completed the journey of two hours. Now, It will take 10 hours to reach Y and other bus should also take 10 hours to reach this point as their speed are equal.

 Now,  Consider distance=d

   Speed of either bus=d/10  (where, 10=time in hours)

Relative speed=d/10 + d/10 = d/5  (As they are heading in opposite direction)

So, it means collectively they complete d/5 distance in one hour.

So, for crossing the distance d, they will take time = 5 hours from the initial time which was 8 pm. So, they meet each other at 1 AM.

Step-by-step explanation:

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