Question

it takes 15 minutes for an electrical kettle to heat a certain quantity of water in grams from 0°C to 100°C.
If it takes 80 minutes to boil water into steam, find the latent heat of steam.
Plssss Help !!!!​

Answer 1

Answer: we know that s= dQ/mdt

or dQ = s m dt

or dQ = 4180 m 100 J          specific heat capacity of water is 4186 J $kg^{-1}$$K^{-1}$

or dQ = 418600m J

latent heat L = dQ/m = 418600J/kg

Explanation:

Answer 2

Answer:

we know dQ = msdT = m 1 ( 100) cal   ( specific heat of water is 1 cal /gK)

 100 m cal

so heat absorbed in 15 minutes = 100 m cal

heat absorbed in 80 minutes = 100 * 80 /15 = 100 * 5.333= 533.33m cal

but dQ = mL

or L = dQ / m = 533.33 cal /g = 533.33 * 4.18 *1000 J/kg = 2229319.4 J/kg

mukeshkumar34225 forget to divide and multiply dQ by 80 and 15 respectively

you will find same anwer if you divide L =418600 by 15 and multiply by 80.