It takes 22 hours for a hosepipe with a flow of 12 litres per minute to fill a swimming pool. How long will it take if its flow is reduced to 5 litres per minute?
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Step-by-step explanation:
t2 = 52.8 hours
it will take 52.8 hours if its flow is reduced to 5 litres per minute.
The volume of the swimming pool can be written as;
Volume V = flow rate × time
V = R×t
V = R1×t1 = R2×t2
R1×t1 = R2×t2
t2 = R1×t1/R2 ........1
Given;
Flow rate R1 = 12 litres per minute
Flow rate R2 = 5 litres per minute
time t1 = 22 hours
Substituting the given values into equation 1;
t2 = R1×t1/R2 = 12×22/5
t2 = 52.8 hours
it will take 52.8 hours if its flow is reduced to 5 litres per minute.
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