Question

it takes 24 hours to fill a swimming pool using pipes. if the pipe of larger diameter is used for 8 hours and the pipe of smaller diameter is used for 18 hours only half of the pool is filled how long would each pipe take to fill the swimming pool

solve this using cross multiplication method


guys please help me out from this please guys tell the answer fast​

Answer 1

Answer:

40 hrs

Hope this attachment helps uh...

Answer 2

Answer:

Let there are two pipes A and B and diameter of A is larger than B.

Now suppose that

Pipe A take x hours and Pipe B takes y hours to fill the pool separately .

In 1 hour pipe A can fill the pool =

x

1

In 1 hour pipe B can fill the pool=

y

1

If both pipe are together then they take 12 hour to fill the pool.

If the are togther then in 1 hour they fill the pool.

x

1

+

y

1

=

12

1

−−−−(1)

Now

In 4 hour pipe A can fill the pool is=

x

4

In 9 hour pipe B can fill the pool is=

y

9

than they fill half of the pool,so

x

4

+

y

9

=

2

1

−−−−−(2)

Now Let

x

1

=P &

y

1

=Q and puuting in equation 1 &2, than

P+Q=

12

1

⇒12P+12Q=1−−−−(3)

And

4P+9Q =

2

1

⇒8P+18Q=1−−−−−(4)

Now solving equation 3 & 4

Equation (3) multiplying by 2 and (4) multiplying by 3 and substract.

⇒−30Q=−1

⇒Q=

30

1

now put value of Q in equation 3

We get P=

20

1

So we found

P=

20

1

& Q=

30

1

So x=20 and y=30

Hence the A pipe would take 20 hours and the pipe B would take 30 hours separately