Question

It takes 83 mL of a 0.45 M NaOH solution to neutralize 235 mL of an HCl solution. What is the concentration of the HCl solution?

Answer 1

Answer:

concentration of HCl = 0.16M

Explanation:

for NaOH:

0.45 M = mol/litre

therefore, n(NaOH) = 0.45mole x 83 / 1000

n(NaOH) = 0.037 moles of NaOH.

1NaOH +1HCl ⇒ 1NaCl + 1H2O

1 mole of NaOH = 1 mole of HCl

thus, n(HCl) = 0.037 moles

concentration of HCl = mole/litre

                                   = 0.037 / 0.235

                                   = 0.157

                                   ≈ 0.16 M

HOPE THIS HELPS!!

Answer 2

Answer:

0.16 M of HCl

Explanation:

Formula: M1V1 = M2V2

M1V1 = KNOWN

M2V2 = UNKNOWN

Convert ml to L

83/1000 = 0.083 L

235/1000 = 0.235 L

0.45 x 0.083 = M2 x 0.235

0.03735 = M2 x 0.235

0.03735/0.235 = M2

0.158 CONVERT IT TO THE NEARST

SO IT WILL BE

0.16 M

HCL SOLUTION:

0.16 M OF HCL