It takes me 8 hrs to reach city A from B, if i increase my speed by 6 km hr it takes me 1 hr 20 min less. Find the distance between the two cities.
Answers
Answered by
1
Let the original speed be s, and distance between A and B is d.
s = d/8.....(1)
For 2nd case, we have
s + 6 = d / (6 hr 40 min)
6 hr 40 min = 6 2/3 hr or 20/3 hr
s + 6 = d / (20/3)
s + 6 = 3d / 20....(2)
Putting (1) in (2)
d/8 + 6 = 3d/20
5d/40 + 240/40 = 6d/40
d/40 = 240/40
d = 240
Distance between A and B is 240 km
s = d/8.....(1)
For 2nd case, we have
s + 6 = d / (6 hr 40 min)
6 hr 40 min = 6 2/3 hr or 20/3 hr
s + 6 = d / (20/3)
s + 6 = 3d / 20....(2)
Putting (1) in (2)
d/8 + 6 = 3d/20
5d/40 + 240/40 = 6d/40
d/40 = 240/40
d = 240
Distance between A and B is 240 km
Answered by
0
Hello Dear.
Here is the answer---
Let the distance between the Cities A and B is x km.
In First Case,
Distance = x km.
Original Time = 8 hrs.
∵ Speed = Distance/Time
∴ Speed = x/8 km/hr.
Now, In Second Case,
Speed = Original Speed + 6 km/hr.
= x/8 + 6
= (x + 48)/8 km/hr.
1 hrs + 20 min. = 60 min. + 20 min.
= 80 min.
= 80/60 hrs.
= 4/3 hrs.
Now,
Time = Original Time - 1 hrs + 20 min.
= 8 hrs. - 4/3 hrs.
= (24 - 4)/3 hrs.
= 20/3 hrs.
∵ Speed = Distance/Time
∴ (x + 48)/8 = x/(20/3)
⇒
⇒ 20 × (x + 48) = 8 × 3x
⇒ 20x + 960 = 24x
⇒ 4x = 960
⇒ x = 240 km.
∴ Distance between the two cities is 240 km.
Hope it helps.
Here is the answer---
Let the distance between the Cities A and B is x km.
In First Case,
Distance = x km.
Original Time = 8 hrs.
∵ Speed = Distance/Time
∴ Speed = x/8 km/hr.
Now, In Second Case,
Speed = Original Speed + 6 km/hr.
= x/8 + 6
= (x + 48)/8 km/hr.
1 hrs + 20 min. = 60 min. + 20 min.
= 80 min.
= 80/60 hrs.
= 4/3 hrs.
Now,
Time = Original Time - 1 hrs + 20 min.
= 8 hrs. - 4/3 hrs.
= (24 - 4)/3 hrs.
= 20/3 hrs.
∵ Speed = Distance/Time
∴ (x + 48)/8 = x/(20/3)
⇒
⇒ 20 × (x + 48) = 8 × 3x
⇒ 20x + 960 = 24x
⇒ 4x = 960
⇒ x = 240 km.
∴ Distance between the two cities is 240 km.
Hope it helps.
Similar questions
6d/40 = (5d + 240)/40
6d = 5d + 240
d = 240.