it the highway overpass is represented by x²-2x-8 then its zeroes are
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x² - 2x - 8 = 0
x² - 4x + 2x - 8 = 0
x(x - 4) + 2(x - 4) = 0
(x + 2) (x - 4) = 0
x = -2 or x = 4
its zeroes are -2 and 4
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Answer:
X^2 -2x-8
X^2 -4x+2x -8
X(x-4)+2(x-4)
(x+2) (x-4)
X=-2 ; x= +4
Step-by-step explanation:
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