it the nth term of an AP is (5n+1) then the sum of it first three terms is :a)33b)15c)12d)21
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Answer :
33
Solution :
- Given : nth term , a(n) = 5n + 1
- To find : Sum of 1st terms , S(3) = ?
We have ;
nth term , a(n) = 5n + 1
Thus ,
First term , a(1) = 5×1 + 1
a(1) = 5 + 1
a(1) = 6
Also ,
Second term , a(2) = 5×2 + 1
a(2) = 10 + 1
a(2) = 11
Now ,
Third term , a(3) = 5×3 + 1
a(3) = 15 + 1
a(3) = 16
Now ,
The sum of the first three terms will ;
=> S(3) = a(1) + a(2) + a(3)
=> S(3) = 6 + 11 + 16
=> S(3) = 33
Hence , S(3) = 33 .
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