Question

It the radius of the sphere is
doubled and the ratio of volume
of the new sphere to the original
​

Answer 1

Step-by-step explanation:

let the original radius be R and increased radius be 2R

Volume of original sphere V1 = 4/3πR³ .......1

Volume of sphere after doubling it's radius

V2 = 4/3π(2R)³ = 4/3π8R³.........2

V2 : V1 = 4/3π*8R³ : 4/3πR³

V2 : V1 = 8 : 1