Question

it theta is an acute angle and
sin theta=coso theta, find the value of
2 tan^theta& sin^2theta-1.​

Answer 1

Theta is an acute angle
This means that theta lies in the first quadrant

We know that
Tan theta= sin theta / cos theta
Since sin theta = cos theta
Tan theta= 1/1
So, perpendicular is 1
Base is 1
Now we apply Pythagoras theorem,
1^2 + 1^2= h^2
➡️ root 2= h
Now you have the perpendicular, base and hypotenuse

We have to find 2tan^2 theta
2tan^2 theta= 2 x 1^2= 2

Now, sin^2theta-1= -cos^2theta ( cos^2theta + sin^2theta = 1 )
Cos theta= base/perpendicular= 1/root2
- cos^2theta= -(1/root2)^2= -1/2

Answer 2

Answer:

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