Question

It vertical separation between the masses in the adjacent figure at t = 0 is 30 m the time after which
they are adjacent to each other is sec lg = 10 ms -
IL
1) 2
2 6
3) 3
4kg
4) 5
2 kg
The reading in the spring balance is​

Answer 1

Answer:

6

Explanation:

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Answer 2

Answer:

3

Explanation:

Given question is

If vertical separation between the masses in the adjacent figure at t = 0 is 30 m the time after which they are adjacent to each other is sec [g=10ms−2] [g=10ms−2]

force acting on block 4kg

$f = mg = 4 \times 10 = 40n$

40N force is acing on 4kg block

Net force acting on block 4kg and acceleration downwards equation is

$40-t=4a - - - - 1$

force acting on block 2kg

$f = 2 \times 10 = 20n$

20N force is acting on 2kg block and acceleration acting upwards

equation is

$t - 20 = 2a \\ t = 20 + 2a - - - 2$

from equation 1 and 2