it was asked for board2020 science
please solve it
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Since the resistance of the wire is doubled
Therefore the new resistance will be=6ohm+6ohm=12ohm
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Answer:
1.5Ω
Explanation:
If a wire was doubled on itself :
- Length gets decreased to half its original.
- Area of cross section is doubled.
Now, given that original resistance is 6Ω, if its length was 'l' and area of cross section be 'A',
6Ω = (p)(l/A). - (1)
Now, new resistance 'R',
=> R = (p)(l/2)(1/2A)
=> R = (p)(l/4A)
=> R = 1/4(p)(l/A). - (2)
From (1) and (2),
=> R = 1/4(6Ω)
=> R = 6/4Ω
=> R= 1.5Ω
Thus, new resistance would be 1.5Ω.
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