Math, asked by Bhupender999, 1 year ago

It was compulsory to get 36% marks in a paper to Manoj to pass it. He got only 24% marks and

failed by 9 marks. Total marks of paper was ?

Answers

Answered by 27jenny

heyyy mate...
total marks = 100
passing marks = 36
attempt / got marks = 24
hope it helps u

Bhupender999: formula ?

27jenny: total marks × %age /100

27jenny: agar or koi doubt ho to puch lena

Bhupender999: 36%-24%=12% 12%=9 total marks= 9/12×100 = 75 right answer

27jenny: what

Bhupender999: answer is 75

27jenny: ohhb

27jenny: sorry

Bhupender999: koi ni thanx

27jenny: it's my pleasure

Answered by Shumita

Answer:

Step-by-step explanation:

x= Total marks

The difference between 36% and 24% is 9 marks. Since he failed exam by lack of 9 marks or he managed only to score only 24%. While he must score 36%.

Therefore,

36% of x - 24% of x = 9

$\frac{36}{100} x - \frac{24}{100}x = 9$

$0.12x = 9 \\ x = 75$

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