It was found that 380mL of a gas at 27◦C and 800mm of Hg weighed 0.455g. Find the molecular weight of the gas.
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using the ideal gas equation ---- PV = nRT
P =800 my of Hg = 1.05 atm
V = 380 ml =0.38 L
T =27c = 273 + 27 =300 K 1.05*0. 38 = n (25/ 3)*3 00
1.05*0.38/(7500/3) = n
n = 1.197/7500 = 0.0001596 mol
now,0.0001596 mol has weight 0.455g
so, 1 mol has weight = 0.455/0.0001596
molecular weight = 2850.8 gm
P =800 my of Hg = 1.05 atm
V = 380 ml =0.38 L
T =27c = 273 + 27 =300 K 1.05*0. 38 = n (25/ 3)*3 00
1.05*0.38/(7500/3) = n
n = 1.197/7500 = 0.0001596 mol
now,0.0001596 mol has weight 0.455g
so, 1 mol has weight = 0.455/0.0001596
molecular weight = 2850.8 gm
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