Question

It was Neha’s birthday and she bought chocolates for the class. Her classmates ate 2/5th of the chocolates on the day of her birthday and on the next day, they ate 3/4th of the remainder. How many chocolates had she initially got if the number of chocolates left on day 3 were 75​

Answer 1

Answer:

500

Step-by-step explanation:

let the no. of chocolates be x

the no. of chocolates they ate on 1st day

= (x - 2x/5)=3x/5

the no. of chocolates they ate on 2nd day

=

$(\frac{3x}{5} - \frac{3}{4}( \frac{3x}{5})) = \frac{3x}{20}$

it is given the no. of chocolates left on 3rd day is 75

so 3x/20=75

x=500