It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the
Jaguar skidded to a stop with a constant acceleration of -3.90 m/s2 , determine the speed of the Jaguar
before it began to skid.
Answers
Answer :-
Speed of the Jaguar before it began to skid is 47.56 m/s .
Explanation :-
We have :-
→ Length of skid marks = 290 m
→ Acceleration of the jaguar = - 3.90 m/s²
• Since the jaguar finally stops by skidding, so it's final velocity will be zero.
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Now, according to the 3rd equation of motion :-
v² - u² = 2as
Where :-
• v is the final velocity.
• u is the initial velocity
• a is the acceleration.
• s is distance.
Substituting values, we get :-
⇒ 0 - u² = 2(-3.90)(290)
⇒ - u² = - 2262
⇒ u² = 2262
⇒ u = √2262
⇒ u = 47.56 m/s
Answer:
Given :-
- It was once a recorded that a Jaguar left skid marks that were 290 m in length.
- The Jaguar skidded to stop with a constant acceleration of - 3.90 m/s².
To Find :-
- What is the speed of the Jaguar before it began to skid.
Formula Used :-
3rd Equation of Motion :
where,
- v = Final Velocity
- u = Initial Velocity
- a = Acceleration
- s = Distance Covered
Solution :-
Given :
Distance Covered (s) = 290 m
Acceleration (a) = - 3.90 m/s²
Final Velocity (v) = 0 m/s
According to the question by using the formula we get,
The speed or initial velocity of the Jaguar before it began to skid is 47.56 m .