Question

It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the
Jaguar skidded to a stop with a constant acceleration of -3.90 m/s2 , determine the speed of the Jaguar
before it began to skid.​

Answer 1

Step-by-step explanation:

“It was once recorded that a Jaguar left skid marks that were 290 m in length.”

Here, length means distance is 290 m.

“Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s².”

Acceleration = -3.90 m/s² (negative sign shows retardation) and final velocity is 0 m/s.

We have to find the speed of the jaguar before it began to skid. Means initial velocity.

Using the Third Equation Of Motion,

v² - u² = 2as

Substitute the known values

→ (0)² - u² = 2 × (-3.90) × 290

→ - u² = - 2262

→ u = √2262

→ u = 47.56

Therefore, the initial velocity of the or speed of the jaguar before it began to skid is 47.56 m/s.

Answer 2

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We are given: s = 290, u = ?, v = 0 (comes to rest),

a = -3.9 and t is irrelevant… using v^2 = u^2 + 2as…

substituting gives: 0 = u^2 + 2*(-3.9)*290, Rearranged

gives: u = sqrt(2262) which is 47.5604878…. = 47.6

Hope this helps you ❤️