It was the semester exam day, Vidhya caught the college bus. She enjoyed traveling by bus. Moving at 6 mph, the bus took Vidhya to college at the right time. She finished her exam and had a chit chat with her friends and suddenly she realized that it was 6 pm and she had missed the college bus. She decided to walk back home at 4 mph. What is her average speed for the day?
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the average speed is 6+4/2=5mph
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ANSWER:
d
EXPLANATION:
The average speed (AS) of any object is the total distance travelled by that object divided by the lapsed time to cover the distance. AS is essential to know the rate at which a trip happens. All through a trip, the speed may differ from time to time. In such case, finding the AS is essential to have an approximation of the rate at which the trip is completed.
Distance taken by the bus to reach college = 6mph (x)
Distance by Vidya to reach home = 4mph (y)
Total distance covered = 2xy
Total time taken = x+y
Therefore Average Speed =2xy/x+y
=(2×6×4)/(6+4)
Average speed =(2×6×4)/10
=48/10
= 4.8 mph
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