Question

(it) What are the roots of the quadratic equation = 9?
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Answer 1

Answer:

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Step-by-step explanation:

Roots of the given Quadratic equation are real and different.

Step-by-step explanation:

Given Quadratic Equation:

9x² - 6x - 2 = 0

To find: Nature of the roots of the Quadratic Equation.

We know that nature of the roots depend on the value of discriminant, D = b² - 4ac

If D > 0 then roots are real and different.

If D = 0 then roots are real and same.

If D < 0 then roots does not exist or say roots are complex conjugate or imaginary number.

here, a = 9 , b = -6 and c = -2

So, D = (-6)² - 4(9)(-2) = 36 + 72 = 108

Since, D > 0

⇒ Roots are Real and different.

Therefore, Roots of the given Quadratic equation are real and different.