Question

It would be very nice if someone could answer this <3​

Answer 1

Answer:

8 or 32

Step-by-step explanation:

$d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2}}$

(- 7 + 2)² + (y - 20)² = 13²

25 + y² - 40y + 400 - 169 = 0

y² - 40y + 256 = 0

D = (- 40)² - 4(256) = 1600 - 1024 = 24²

$y_{12}$ = (40 ± 24) / 2

$y_{1}$ = 32

$y_{2}$ = 8

Thus, number can be 8 or 32.