Question

. It (x+1) and (x-1) are are factors of
P (x3 + x² - 2x +q) find p and q​

Answer 1

Answer:

I don't think my answer is right just consult Ur teacher first☺️

Step-by-step explanation:

As (x-1) is factor of q(X)

x-1 =0

X=1

putting the Value of X in q(X)

q(X) = P[x³ + x² - 2x +q]

let q(X) =0

P[1³ + 1² - 2*1 +q] =0

P[1+1-2+q]=0

P[2-2+q]=0

P[0+q]=0

P[q]=0

PQ=0

This implies P =0

q=0

hoping this answer is right plzz consult Ur teacher