It zeroes of polynomial x² + ( a +1) x +b are 2 &- 3,
then find the value of (a+b).
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Step-by-step explanation:
x
2
+(a+1)x+b is the quadratic polynomial.
2 and −3 are the zeros of the quadratic polynomial.
Thus, 2+(−3)=
1
−(a+1)
=>
1
(a+1)
=1
=>a+1=1
=>a=0
Also, 2×(−3)=b
=>b=−6
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