Question

ITA is a 2x2order singular matrix with 1st row 11 4 1 and 2nd row[2x] then value of x is​

Answer 1

Answer:

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Answer 2

Answer:

The value of x is $\frac{82}{11}$

Step-by-step explanation:

The given matrix is

$A=\left[\begin{array}{22}11&41\2&2&x\end{array}\right]$

Singular matrix: Singular matrix is the square matrix whose determinant is zero

Given that A is a singular matrix, therefore, the determinant of A is zero

| A | = 0

$|A|=\left|\begin{array}{22}11&41\2&2&x\end{array}\right|$

11x - 41(2) = 0

11x = 82

$x=\frac{82}{11}$

Therefore the value of x is $\frac{82}{11}$