Question

itf sin theta =a/b find cos thet

​

Answer 1

Answer:

what is this the question I don't mean

Explanation:

can you explain it

Answer 2

Answer:

Cos = root under b^2-a^2/b

Explanation:

Sin = a/b = p/h

Using Pythagoras Theorem

b = root under h^2-p^2

= root under b^2-a^2

Cos = b/h = b^2-a^2/b