ithe photoelectric work function of a metal surface is 4.14 EV .the cutoff wavelength for this is
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Cutoff wavelength = 0.3 micrometer
Explanation:
Given: Photoelectric work function of a metal surface is 4.14 EV
Find: Cutoff wavelength.
Solution:
W = 4.14 e V
Converting W to Joules, we get: 4.14 * 1.6 * 10^-19 J
W = h c / λo
Where λo is the cutoff wavelength, h = 6.626 * 10-34, and c is the speed of light in vacuum.
So λo = h c / W
= 6.626 * 10^-34 * 3 * 10^8 / (4.14 * 1.6 * 10^-19)
= (6.626 * 3 / 4.14 * 1.6) * 10^-7
= 3.0009 * 10^-7 m
= 0.3 micrometer
Cutoff wavelength = 0.3 micrometer
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