Math, asked by jayrishsinghachom, 8 months ago

its a tricky question
Three friends visit a restaurants . There they have one samosa each. The waiter gave them the bill . The total cost was Rs30 . Each of them contribute Rs10 each . The owner of the restaurant thought to take only Rs25 and told his waiter to repay the extra i.eRs5 to them .it was very tough for the waiter as Rs5 cannot be share equally among the three friends . So the waiter decided to pay only Rs1 to each of them and he kept the remaining Rs2 .Now ,since Rs1 is returned to each of them then they all contribute Rs9 each for their meal. now the total is 3*Rs9 i.eRs27 .but the waiter took Rs2 . now Rs27 + Rs2 = Rs29 . where is the missing Rs1 ??????????????????????
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Answers

Answered by sufyan08
0

Answer:

O my God....Sry but I don't have time to read this story....

Answered by Anonymous
1

Answer:

Bill received by the 3 persons = Rs 30

Discount given by manager = Rs 5

So, Cost for food = Rs (30 - 5) = Rs 5

But, the waiter become greedy So, he took 2 rupees from the 5 rupees.

Waiter return one-one rupee to the three persons. So, Three persons total bills = 9 x 3 = Rs 27

As we know that, the waiter took Rs 2 and also that it was already counted in the bill so that it becomes Rs 27.

And the money given to three persons is Rs 3 when we add this money to the bill and the total amount becomes 30rs

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