Question

its being given that 1 is a zero of the polynomial (7x-x^3-6). Find the other zeros

Answer 1

Given that one zero is 1
So one of the factor is (x-1)
[AS x =1
x-1=0]
By dividing polynomial -x^3 -7x-6 by (x-1) we will get other factor as -x^2 -x+6
By factorising-x^2 -x+6
We will get
-x^2 -x+6
-x^2 -3x+2x +6
-x (x+3) +2 (x+3)
(2-x)(x+3)

finding other zeroes
(2-x) =0
-x= -2
x=2

(x+3) =0
x =-3
So the other zeroes are 2 and -3