Physics, asked by adityaguptafbg3825, 1 month ago

its boiling point, stored in a vacuum flask. The boiling point of nitrogen is -196 °C.
The liquid nitrogen reaches its boiling point of -196 °C. A small piece of metal at 20 °C is lowered slowly into the liquid nitrogen. Bubbles form within the liquid nitrogen as it boils. The small piece of metal has a mass of 50 g. When it is lowered into the liquid nitrogen, the metal cools to -196 °C. The specific heat capacity of the metal is 0.39 J/(g K). The specific latent heat of vaporization of nitrogen is 200 J/g. (i) Calculate the thermal energy lost by the metal as it cools

Answers

Answered by saifalam000000678
0

Explanation:

its boiling point, stored in a vacuum flask. The boiling point of nitrogen is -196 °C.

The liquid nitrogen reaches its boiling point of -196 °C. A small piece of metal at 20 °C is lowered slowly into the liquid nitrogen. Bubbles form within the liquid nitrogen as it boils. The small piece of metal has a mass of 50 g. When it is lowered into the liquid nitrogen, the metal cools to -196 °C. The specific heat capacity of the metal is 0.39 J/(g K). The specific latent heat of vaporization of nitrogen is 200 J/g. (i) Calculate the thermal energy lost

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