Its easy question from trigonometry plz solve this Q7
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hafeezhtech:
Obaid is the answer 74 ?
7/4 sorry
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sin 90°= 1,
cos 45°=1/√2
cos60°=1/2,
cos 0°=1,
sin 45°=1/√2,
sin 30°=1/2,
therefore, the solution is,
[1+1/√2+1/2] [1-1/√2+1/2]
[2√2+2+√2/2√2] [2√2-2+√2/2√2]
[3√2+2\2√2] [3√2-2/2√2]
(3√2/2√2)^2- (2/2√2)^2
18/8-4/8
14/8
7/4 is your correct answer
PLZ MARK AD THE BRAINLIEST
PLZ,BE BRAINLY
cos 45°=1/√2
cos60°=1/2,
cos 0°=1,
sin 45°=1/√2,
sin 30°=1/2,
therefore, the solution is,
[1+1/√2+1/2] [1-1/√2+1/2]
[2√2+2+√2/2√2] [2√2-2+√2/2√2]
[3√2+2\2√2] [3√2-2/2√2]
(3√2/2√2)^2- (2/2√2)^2
18/8-4/8
14/8
7/4 is your correct answer
PLZ MARK AD THE BRAINLIEST
PLZ,BE BRAINLY
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