Question

Its found that the sum of two numbers is 10 and the sum of their reciprocals is find the number​

Answer 1

Answer:

your question is half....plz write the whole question.....

Answer 2

Answer:

The numbers are 2 and 8.

Step-by-step explanation:

I believe your Question was,

"Its found that the Sum of two numbers is 10 and the sum of their reciprocals is (5/8). Find the numbers."

Now,

Let the number be x and y.

Thus, according to the Question,

x + y = 10 ------ 1

also,

(1/x) + (1/y) = (5/8)

Taking LCM = xy

(y/xy) + (x/xy) = (5/8)

(x + y)/xy = (5/8)

From eq.1 we get,

(10)/xy = (5/8)

Cross multiplying we get,

8 × 10 = 5 × xy

80 = 5xy

xy = 80/5

xy = 16

Hence,

We must two numbers whose Sum = 10 and Product = 16

Now,

16 = 1 × 16

16 = 2 × 8

16 = 4 × 4

Here, 2 and 8 add upto 10 and give product as 16.

So, the numbers should be 8 and 2

We can also check this,

1. 8 + 2 = 10

10 = 10 (True)

2. (1/8) + (1/2) = (5/8)

Taking LCM = 8

(1/8) + (4/8) = (5/8)

(1 + 4)/8 = (5/8)

(5/8) = (5/8) (True)

So, they are correct.

Thus,

The numbers are 2 and 8.

Hope it helped and believing you understood it........All the best