Question

its it possible to design a rectangular mango grove whose length is twice it's breadth and area is 800m²? if so ,find its length and breadth​

Answer 1

Answer :

• Length of the rectangular groove = 40m
• Breadth of the rectangular groove = 20m

Given :

• Is it possible to design a rectangular mango groove whose length is twice it's breadth and area is 800m².

To Find :

• Length and breadth of the rectangular mango groove.

Solution :

Here

• Area of the rectangular groove = 800m²

Let

• Breadth of the rectangular groove = x
• Length of the rectangular groove = 2x

As we know that

• Area of a rectangle = l × b

Where

• l = length
• b = breadth

Put the values in the formula

Now,

According to question :

→ l × b = 800

→ 2x × x = 800

→ 2x² = 800

→ x² = 800/2

→ x² = 400

→ x = √400

→ x = 20

Now

• Breadth of the mango groove = x = 20m
• Length of the rectangular groove = 2x = 20 × 2 = 40m

Hence, the length and breadth of the rectangular groove are 40m and 20m respectively.

Answer 2

$\huge{\underline{\mathtt{\blue{Answer}}}}$

GIVEN

• $\sf{Area \:of \:rectangle = 800cm²}$
• $\sf{The \:length \:is \:twice \:it's \:breath}$

TO FIND

• $\sf{Length = ?¿}$
• $\sf{Breadth = ?¿}$

NOW ;

$~~~~~\sf{\:Breath \:of \:rectangular = x}$

$~~~~~\sf{\:Length \:of \:rectangular = 2x}$

We know the formula ;

${\green{\overline{\green{\underline{\blue{\boxed{\orange{\mathtt{Area = Length × Breadth}}}}}}}}}$

$~~~~~\sf{A = L × B}$

$\sf{:⟹ 800 = 2x × x}$

$\sf{:⟹ 800 = 2x²}$

Transporting To LHS and RHS

$\sf{:⟹ 2x² = 800}$

$\sf{:⟹ x² = \frac{800}{2}}$

$\sf{:⟹ x² = \frac{\cancel{800}^{400}}{\cancel{2}^{1}}}$

$\sf{:⟹ x² = 400}$

$\sf{:⟹ x = \sqrt{400}}$

$\sf{:⟹ x = ± \sqrt{400}}$

$\sf{:⟹ x = ± 20}$

So : - 20 and + 20 are the result !!

Here Negative is neglected :

So !;

• $\sf{Breath = 20}$

$~~~~~~\sf{Length = 2x}$

$~~~~~~\sf{L = 2(20)}$

• $\sf{Length = 40}$

So the Length of the rectangular mango grove = 40cm

So the Breadth of the rectangular mango grove = 20cm