its math
give me the crt answer
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Answer:
In ∆ BCD,
BC+CD > BD_____(1)
In ∆ACD,
AD+ CD >AC_____(2)
In ∆ ABD,
AB + AD > BD______(3)
In ∆ ABC,
AB+ BC > AC______(4)
adding (1),(2),(3)&(4)
we get,
2(AB+BC+CD+DA) > 2(AC+BD)
thus , AB+BC+CD+DA > AC+BD
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