Question

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Q) Sun's mass is 3.2 x 10^5 times the earth's mass. Sun is 400 times as far as from the earth as the
moon is. Find the ratio of magnitude of the pull of the sun on the moon to that of the pull of the
earth on the moon.
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Answer 1

Explanation:

:. m = moon mass

:. ms = sun mass

:. me = earth mass

:. r^ms = is the centre to centre distance from the sun to moon

:. r^me = is the centre to centre distance from the earth to moon

:. f^ms = the magnitude of gravitational force external on the moon by the sun

:. f^me = the magnitude of gravitational force external on the moon by the earth

----- fms = G Msm / r^2ms

fme = G Mem / r^2mb

Ms = 3.2×10^5×me

rms = 400×rme

Fms/Rme = GMsm / r^2ms / Gmem / r^2me

Fms / Fme = MSr^2me / Mer^2ms

Fms / Fme = 3.2 ×10^5×Mer^2me/

Me×(400×r^me)

Fms / Fme = 3.2×10^5/160000

= 2