ITS URGENT.NO SPAM AND NO IRRELEVANT ANSWER. A stone is thrown vertically upward with a velocity of 9.8m/s .(i) What is the time taken to reach the maximum height.(ii)What is the maximum height reached.(iii) Time taken to reach the ground (iv)What is the velocity when it reaches the ground.
Answers
QUESTION:-
stone is thrown vertically upward with a velocity of 9.8m/s
.(i) What is the time taken to reach the maximum height.
(ii)What is the maximum height reached.
(iii) Time taken to reach the ground
(iv)What is the velocity when it reaches the ground.
ANSWER:-
To get the maximum height h reached by stone, we need to use the formula, "v2 = u2 - 2gh ", where v is final velocity which is zero here, u is initial velocity and g is acceleration due to gravity.
hence h = u /(2g) = (4.9x4.9)/(2x9.8) = 1.225 m
To get the time taken to reach maximum height h, we need to use the formula, "v = u- gt".
since final velocity v = 0, t = u/g = 4.9/9.8 = 0.5 s
Stone reaches the ground with same velocity as it was projected upwards, ie, its velocity when it reaches ground is 4.9 m/s
Downward flight time of stone is same as upward flight time, Hence time taken to reach ground from starting time = 0.5+0.5 = 1