Question

ITS URGENT!!!!
p=10000 r=8 t=1 year interest being compounded half-yearly with formula​
with full explanation​

Answer 1

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$given \\ p = 10000 \\ r = 8 \\ t = 1 \\ \\ using \: formula \\ a = p( 1 + \frac{r}{100} ) {}^{n} \\ a = 10000(1 + \frac{8}{100} ) {}^{1} \\ a = 100(1 + 8) \\ a = 100(9) \\ a =₹ 900 \\ \\ now \\ c = amount - principal \\ c = 10000 - 900 \\ c = ₹9100 \\ \\ maybe \: it \: is \: correct.......$

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Answer 2

ANSWER:

A = 10,816

A = P + I where

P (principal) = 10,000

I (interest) = 816

CALCULATION STEPS:

First, convert R percent to r a decimal

• r = R/100
• r = 8%/100
• r = 0.08 per year

Then, solve our equation for A

• A = P(1 + r/n)^nt
• A = 10,000.00(1 + 0.04/2)^(2)(1)
• A = $10,816.00

The total amount accrued, principal plus interest, from compound interest on an original principal of 10,000 at a rate of 8% per year compounded 2 times per year over 1 years is 10,816