Question

Its urgent please answer !!​

Answer 1

Step-by-step explanation:

Given; circle with centre O in which chords AB and CD intersect at M.

To Prove: AM = DM and CM = BM

In ΔAOM and ΔDOM

OA = OD (radii)

OM = OM (common side)

So, ΔAOM ≈ Δ DOM

Hence, AM = DM proved

It is given that AB = CD

So, AB – AM = CD – DM

Or, CM = BM proved