its urgent....
please factorise 3x^2+8root2x-6
Answers
Answered by
2
Hi friend!!!
Solution is given.
3x²+8√2x-6
=3x²+9√2x-√2x-6
=3x(x+3√2)-√2(x+3√2)
=(3x-√2)(x+3√2)
Therefore,( 3x-√2) and (x+3√2) are the factors of the given polynomial.
I hope this will help u;)
Solution is given.
3x²+8√2x-6
=3x²+9√2x-√2x-6
=3x(x+3√2)-√2(x+3√2)
=(3x-√2)(x+3√2)
Therefore,( 3x-√2) and (x+3√2) are the factors of the given polynomial.
I hope this will help u;)
DhanyaDA:
thanks for the brainliest
welcme
congo your answer is awesome :-)
Thank you ^_^
Urs too @prashant
hehe..thanks
^_^
Answered by
4
So, by using quadratic formula we get
x. = (√2/3) and (-3√2)
that means 3x²+8√2x-6=0 can be written as
(x-(√2/3))(x+3√2)=0
x. = (√2/3) and (-3√2)
that means 3x²+8√2x-6=0 can be written as
(x-(√2/3))(x+3√2)=0
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