Question

its urgent please help

Answer 1

sin^2 (u)=(1-cos2u)/2
=£sin^2 (3x)dx
=£(1-cos2 (3x)/2dx
=(1/2) £dx-(1/2) £cos6xdx
=£(1/2)dx-(1/2)(1/6) £cos6xdx
=(1/2)x-(1/2)sin6x+c

Answer 2

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