Question

Its urgent plzz help solve this

Answer 1

Step-by-step explanation:

HELLO DEAR,

MEDIAN IS 525

500 - 600 is median class

we know median = \bold{ l + \frac{\frac{n}{2} - cf}{f} * h}l+ f2n−cf∗h

where, l = lower limit of median class = 500

h = class interval = 100 - 0 = 100

∑f_i = n = 100

cf = cumulative frequency before class median = 36 + x

f = median frequency

525 = \bold{ 500 + \frac{\frac{100}{2} - (36 + x)}{20} * 100}500+

20

2

100

−(36+x)

∗100

⇒525 = 500 + {50 - (36 + x)} * 5

⇒525 - 500 = {50 - (36 + x)}*5

⇒25/5 = 50 - (36 + x)

⇒36 + x = 50 - 5

⇒x = 45 - 36

⇒x = 9

and

∑f_i = 76 + x + y

100 = 76 + x + y

9 + y + 76 = 100

y = 100 - 85

y = 15

I HOPE ITS HELP YOU DEAR,

THANKS

Answer 2

Refer to the attachment

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.... I hope it will be helpful....