its very easy questions solve this.
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let side of the square be x.
so
in triangle ACD,
Using Pythagoras Theorem,
(AC)^2+(CD)^2=13.6^2
x^2+x^2=184.96
2x^2=184.96
x^2=92.48
x=9.616
Perimeter of square=9.616×4=38.464
so
in triangle ACD,
Using Pythagoras Theorem,
(AC)^2+(CD)^2=13.6^2
x^2+x^2=184.96
2x^2=184.96
x^2=92.48
x=9.616
Perimeter of square=9.616×4=38.464
panchalAjay9746:
wrong answer
how
se here
where
easy method=ab=7(13.6)/10+0.5=10
ab=bd=cd=ac so abcd=4ab=40cm is right answer
sry dr you are right here correct mathaod
ab=7(13.6)/10+1/2mm=9.52+0.05=9.57 ab=bd=cd=ac so Square abcd=4ab=38.2
your answer is nearest
Answered by
0
Answer:
let side of the square be x.
so
in triangle ACD,
Using Pythagoras Theorem,
(AC)^2+(CD)^2=13.6^2
x^2+x^2=184.96
2x^2=184.96
x^2=92.48
x=9.616
Perimeter of square=9.616×4=38.464
Step-by-step explanation:
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