Question

Its very urgent... Plz answer this question for me...
From chapter trigonometry identities
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Answer 1

Solution :-

Taking LHS,

→ (cosecA - sinA)(secA - cosA)sec²A

Putting :-

• cosecA = (1/sinA)
• secA = (1/cosA)

→ (1/sinA - sinA)(1/cosA - cosA)(1/cos²A)

Taking LCM,

→ {(1 - sin²A)/sinA} * {(1 - cos²A)/cosA} * (1/cos²A)

Now, As we know that, sin²A + cos²A = 1, So,

• 1 - sin²A = cos²A
• 1 - cos²A = sin²A

Therefore,

→ (cos²A/sinA) * (sin²A/cosA) * (1/cos²A)

Or, we can say that,

→ (cos²A * sin²A) / (sinA * cosA * cos²A)

→ (sinA/cosA)

Finally, which is Equal to ,

→ tanA = RHS . (Proved).