Question

Itseca SECA 2 sin A I-COSA​

Answer 1

Step-by-step explanation:

Your answer is these see whether it is right or wrong

Answer 2

Ans. Is 4/5

TanA+SecA=2

SecA=2-TanA

1/cosA=2-tanA

1=2cosA-tanA×cosA

1=2cosA-sinA

1+sinA=2cosA =>(1+sinA)=2cosA ——— eq.1

Sq. Both sides of eq.1 , we get

(1+sin^2A+2sinA)=4cos^2A

(1+1-cos^2A+2sinA)=4cos^2A

2+2sinA=5cos^2A

Dividing while eq by 2 , we get

1+sinA=5/2cos^2A ————eq.2

From eqs. 1 and 2 , we get

2cosA=5/2cos^2A

4/5=cosA

Hence, cosA=4/5