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An electric dipole with dipole moment 4 \times 10^{-9}\; C\, m4×10 −9 Cm is aligned at 30° with the direction of a uniform electric field of magnitude 5 \times 10^{4}\; N C^{-1}5×10 4
NC−1. Calculate the magnitude of the torque acting on the dipole.
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Answer:
An electric dipole with dipole moment
4×
10
−9
C m is aligned at
30
∘
with the direction of a uniform electric field of magnitude
5×
10
4
NC
−1
. Calculate the magnitude of the torque acting on the dipole.
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Electric dipole moment,
E=
4×
10
−9
N/C
Angle made by p with a uniform electric field, θ = 30°
Electric field,
E=
5×
10
4
N/C
Torque acting on the dipole:
τ=
pEsinθ
= 4× 10
−9
× 5× 10
4
× sin30
o
= 20× 10
−5
×
2
1
= 10
−4
Nm
Hence, the magnitude of the torque acting on the dipole is 10
−4
N m.
Step-by-step explanation:
When two bodies are rubbed against each other, a charge is developed on both bodies. These charges are equal but opposite in nature. And this phenomenon of inducing a charge is known as charging by friction. The net charge on both of the bodies is 0 and the reason behind it is that an equal amount of charge repels it. When we rub a glass rod with a silk cloth, charge with opposite magnitude is generated over there. This phenomenon is in consistence with the law of conservation of energy. A similar phenomenon is observed with many other pairs of bodies....