Question

IUPAC for following




please answer me​

Answer 1

Answer:

I don't understand ur question

Answer 2

Answer:

1) 2-bromo 3-keto butanoic acid

2) 4-amino 2-ethyl pentanoic acid

3)hex-2-ene -4-yne

Explanation:

1) in first compound let u take parent chain from left.

parent chain has four carbons including carboxylic carbon. hence it is butanoic acid.

then, bromine is present in 2nd carbon and keto group is present in 3rd carbon. . hence the name is

2-bromo 3-keto butanoic acid

2) main parent chain is considered from left.it has 5 carbons. hence it is pentanoic acid.

then amine group is present in 4th carbon and ethyl group is present in 2 nd carbon. . hence the name is

4- amino 2- ethyl pentanoic acid

3)main parent chain is considered from left.double bond is present in 2 nd carbon amd triple bond os present in 4 rd carbon . hence the name is

hex-2- ene -4- yne