Question

IUPAC Name H3C – HC = C – CH2 – CH – CH 2 - COOH
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Br Cl 3-Chloro 5 - bromo hepta 5 - enoic acid
3- Bromo 5 – Chloro hepta 3 – enoic acid 5 – Bromo 3 – Chloro hepta 3 – enoic acid 5 – Bromo 3 – Chloro hepta – 5 –enoic acid

Answer 1

Answer:

give the structure clearly

and options too

they are not clear to understand